Base | Representation |
---|---|
bin | 110000000110111010… |
… | …1011000000110010011 |
3 | 100212122221110101100011 |
4 | 1200031311120012103 |
5 | 3143040143430001 |
6 | 115243251535351 |
7 | 10315102441111 |
oct | 1401565300623 |
9 | 325587411304 |
10 | 103311311251 |
11 | 3a8a55a6275 |
12 | 180328ba557 |
13 | 9985852405 |
14 | 5000b42ab1 |
15 | 2a49cc3d51 |
hex | 180dd58193 |
103311311251 has 2 divisors, whose sum is σ = 103311311252. Its totient is φ = 103311311250.
The previous prime is 103311311179. The next prime is 103311311263. The reversal of 103311311251 is 152113113301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103311311251 - 217 = 103311180179 is a prime.
It is not a weakly prime, because it can be changed into another prime (103311311291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51655655625 + 51655655626.
It is an arithmetic number, because the mean of its divisors is an integer number (51655655626).
Almost surely, 2103311311251 is an apocalyptic number.
103311311251 is a deficient number, since it is larger than the sum of its proper divisors (1).
103311311251 is an equidigital number, since it uses as much as digits as its factorization.
103311311251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 22.
Adding to 103311311251 its reverse (152113113301), we get a palindrome (255424424552).
The spelling of 103311311251 in words is "one hundred three billion, three hundred eleven million, three hundred eleven thousand, two hundred fifty-one".
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