Base | Representation |
---|---|
bin | 10111011111011000111011… |
… | …100110111100000100001111 |
3 | 111112210112200220110112100002 |
4 | 113133120323212330010033 |
5 | 102020131232202314411 |
6 | 1003420535442354515 |
7 | 30522025136423102 |
oct | 2737307346740417 |
9 | 445715626415302 |
10 | 103312143401231 |
11 | 2aa11485676236 |
12 | b70670395ba3b |
13 | 45853a756775b |
14 | 1b72497916739 |
15 | be25bc81c33b |
hex | 5df63b9bc10f |
103312143401231 has 2 divisors, whose sum is σ = 103312143401232. Its totient is φ = 103312143401230.
The previous prime is 103312143401197. The next prime is 103312143401237. The reversal of 103312143401231 is 132104341213301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103312143401231 - 218 = 103312143139087 is a prime.
It is a super-2 number, since 2×1033121434012312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103312143401194 and 103312143401203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103312143401237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51656071700615 + 51656071700616.
It is an arithmetic number, because the mean of its divisors is an integer number (51656071700616).
Almost surely, 2103312143401231 is an apocalyptic number.
103312143401231 is a deficient number, since it is larger than the sum of its proper divisors (1).
103312143401231 is an equidigital number, since it uses as much as digits as its factorization.
103312143401231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 103312143401231 its reverse (132104341213301), we get a palindrome (235416484614532).
The spelling of 103312143401231 in words is "one hundred three trillion, three hundred twelve billion, one hundred forty-three million, four hundred one thousand, two hundred thirty-one".
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