Search a number
-
+
103312400053 is a prime number
BaseRepresentation
bin110000000110111100…
…1100001111010110101
3100212200000111200220011
41200031321201322311
53143040433300203
6115243331140221
710315114624342
oct1401571417265
9325600450804
10103312400053
113a8a617a305
1218033144671
139985b43b85
145000d477c9
152a49e3b76d
hex180de61eb5

103312400053 has 2 divisors, whose sum is σ = 103312400054. Its totient is φ = 103312400052.

The previous prime is 103312400047. The next prime is 103312400089. The reversal of 103312400053 is 350004213301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88647916644 + 14664483409 = 297738^2 + 121097^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103312400053 is a prime.

It is a super-2 number, since 2×1033124000532 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103312399997 and 103312400033.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103322400053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51656200026 + 51656200027.

It is an arithmetic number, because the mean of its divisors is an integer number (51656200027).

Almost surely, 2103312400053 is an apocalyptic number.

It is an amenable number.

103312400053 is a deficient number, since it is larger than the sum of its proper divisors (1).

103312400053 is an equidigital number, since it uses as much as digits as its factorization.

103312400053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 22.

Adding to 103312400053 its reverse (350004213301), we get a palindrome (453316613354).

The spelling of 103312400053 in words is "one hundred three billion, three hundred twelve million, four hundred thousand, fifty-three".