Base | Representation |
---|---|
bin | 10011001111100110… |
… | …01011011100010011 |
3 | 222200000100201000111 |
4 | 21213303023130103 |
5 | 132124314412201 |
6 | 4425101502151 |
7 | 514010325343 |
oct | 114763133423 |
9 | 28600321014 |
10 | 10331404051 |
11 | 4421898861 |
12 | 2003b71957 |
13 | c88562347 |
14 | 70018cd23 |
15 | 407021b51 |
hex | 267ccb713 |
10331404051 has 2 divisors, whose sum is σ = 10331404052. Its totient is φ = 10331404050.
The previous prime is 10331404021. The next prime is 10331404081. The reversal of 10331404051 is 15040413301.
It is a balanced prime because it is at equal distance from previous prime (10331404021) and next prime (10331404081).
It is an emirp because it is prime and its reverse (15040413301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10331404051 - 27 = 10331403923 is a prime.
It is not a weakly prime, because it can be changed into another prime (10331404021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5165702025 + 5165702026.
It is an arithmetic number, because the mean of its divisors is an integer number (5165702026).
Almost surely, 210331404051 is an apocalyptic number.
10331404051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10331404051 is an equidigital number, since it uses as much as digits as its factorization.
10331404051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 10331404051 its reverse (15040413301), we get a palindrome (25371817352).
The spelling of 10331404051 in words is "ten billion, three hundred thirty-one million, four hundred four thousand, fifty-one".
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