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103320312121219 is a prime number
BaseRepresentation
bin10111011111100000100010…
…100000001000011110000011
3111112211022210012100111112211
4113133200202200020132003
5102020244444400334334
61003424410210402551
730522434436411214
oct2737404240103603
9445738705314484
10103320312121219
112aa14997701496
12b708203590457
1345860a9a3238b
141b72a3077d40b
15be28e9a43a64
hex5df822808783

103320312121219 has 2 divisors, whose sum is σ = 103320312121220. Its totient is φ = 103320312121218.

The previous prime is 103320312121183. The next prime is 103320312121237. The reversal of 103320312121219 is 912121213023301.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (912121213023301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103320312121219 - 215 = 103320312088451 is a prime.

It is a super-3 number, since 3×1033203121212193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (103320312121619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51660156060609 + 51660156060610.

It is an arithmetic number, because the mean of its divisors is an integer number (51660156060610).

Almost surely, 2103320312121219 is an apocalyptic number.

103320312121219 is a deficient number, since it is larger than the sum of its proper divisors (1).

103320312121219 is an equidigital number, since it uses as much as digits as its factorization.

103320312121219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 103320312121219 in words is "one hundred three trillion, three hundred twenty billion, three hundred twelve million, one hundred twenty-one thousand, two hundred nineteen".