Base | Representation |
---|---|
bin | 11110000100110000001… |
… | …11011011001110101101 |
3 | 10122210020112111001000222 |
4 | 33002120013123032231 |
5 | 113412242111000123 |
6 | 2110413425101125 |
7 | 134441143032311 |
oct | 17023007331655 |
9 | 3583215431028 |
10 | 1033344234413 |
11 | 369269976817 |
12 | 148328a877a5 |
13 | 765a045cc6a |
14 | 3802aaa3b41 |
15 | 1bd2dc7e6c8 |
hex | f0981db3ad |
1033344234413 has 2 divisors, whose sum is σ = 1033344234414. Its totient is φ = 1033344234412.
The previous prime is 1033344234397. The next prime is 1033344234457. The reversal of 1033344234413 is 3144324433301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 623337093289 + 410007141124 = 789517^2 + 640318^2 .
It is an emirp because it is prime and its reverse (3144324433301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1033344234413 - 24 = 1033344234397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1033344234463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516672117206 + 516672117207.
It is an arithmetic number, because the mean of its divisors is an integer number (516672117207).
Almost surely, 21033344234413 is an apocalyptic number.
It is an amenable number.
1033344234413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1033344234413 is an equidigital number, since it uses as much as digits as its factorization.
1033344234413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 1033344234413 its reverse (3144324433301), we get a palindrome (4177668667714).
The spelling of 1033344234413 in words is "one trillion, thirty-three billion, three hundred forty-four million, two hundred thirty-four thousand, four hundred thirteen".
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