10334014113 has 4 divisors (see below), whose sum is σ = 13778685488. Its totient is φ = 6889342740.

The previous prime is 10334014109. The next prime is 10334014151. The reversal of 10334014113 is 31141043301.

10334014113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10334014113 - 2² = 10334014109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10334014113.

It is not an unprimeable number, because it can be changed into a prime (10334014153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1722335683 + ... + 1722335688.

It is an arithmetic number, because the mean of its divisors is an integer number (3444671372).

Almost surely, 2^10334014113 is an apocalyptic number.

It is an amenable number.

10334014113 is a deficient number, since it is larger than the sum of its proper divisors (3444671375).

10334014113 is an equidigital number, since it uses as much as digits as its factorization.

10334014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3444671374.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10334014113 its reverse (31141043301), we get a palindrome (41475057414).

The spelling of 10334014113 in words is "ten billion, three hundred thirty-four million, fourteen thousand, one hundred thirteen".