Base | Representation |
---|---|
bin | 110000001000000110… |
… | …1001011011001111011 |
3 | 100212202201100010022011 |
4 | 1200100031023121323 |
5 | 3143130340331042 |
6 | 115251232510351 |
7 | 10316064620233 |
oct | 1402015133173 |
9 | 325681303264 |
10 | 103351105147 |
11 | 3a916005a94 |
12 | 180440ab3b7 |
13 | 9990b761b4 |
14 | 5006140cc3 |
15 | 2a4d534a17 |
hex | 181034b67b |
103351105147 has 2 divisors, whose sum is σ = 103351105148. Its totient is φ = 103351105146.
The previous prime is 103351105133. The next prime is 103351105159. The reversal of 103351105147 is 741501153301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103351105147 - 211 = 103351103099 is a prime.
It is not a weakly prime, because it can be changed into another prime (103351145147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51675552573 + 51675552574.
It is an arithmetic number, because the mean of its divisors is an integer number (51675552574).
Almost surely, 2103351105147 is an apocalyptic number.
103351105147 is a deficient number, since it is larger than the sum of its proper divisors (1).
103351105147 is an equidigital number, since it uses as much as digits as its factorization.
103351105147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 31.
Adding to 103351105147 its reverse (741501153301), we get a palindrome (844852258448).
The spelling of 103351105147 in words is "one hundred three billion, three hundred fifty-one million, one hundred five thousand, one hundred forty-seven".
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