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103351463437 is a prime number
BaseRepresentation
bin110000001000000111…
…0100010111000001101
3100212202202000022210011
41200100032202320031
53143130433312222
6115251244313221
710316100641635
oct1402016427015
9325682008704
10103351463437
113a9162301a2
1218044242811
139990c702c1
1450061d56c5
152a4d5a5c77
hex18103a2e0d

103351463437 has 2 divisors, whose sum is σ = 103351463438. Its totient is φ = 103351463436.

The previous prime is 103351463431. The next prime is 103351463459. The reversal of 103351463437 is 734364153301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98454123076 + 4897340361 = 313774^2 + 69981^2 .

It is an emirp because it is prime and its reverse (734364153301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103351463437 - 215 = 103351430669 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 103351463437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103351463431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51675731718 + 51675731719.

It is an arithmetic number, because the mean of its divisors is an integer number (51675731719).

Almost surely, 2103351463437 is an apocalyptic number.

It is an amenable number.

103351463437 is a deficient number, since it is larger than the sum of its proper divisors (1).

103351463437 is an equidigital number, since it uses as much as digits as its factorization.

103351463437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 272160, while the sum is 40.

The spelling of 103351463437 in words is "one hundred three billion, three hundred fifty-one million, four hundred sixty-three thousand, four hundred thirty-seven".