Base | Representation |
---|---|
bin | 10011010000000101… |
… | …00101110010100011 |
3 | 222200021221221222002 |
4 | 21220002211302203 |
5 | 132131333203011 |
6 | 4425324234215 |
7 | 514056553115 |
oct | 115002456243 |
9 | 28607857862 |
10 | 10335444131 |
11 | 44240a8171 |
12 | 200539b96b |
13 | c8934821c |
14 | 7009213b5 |
15 | 40756dc3b |
hex | 2680a5ca3 |
10335444131 has 4 divisors (see below), whose sum is σ = 10340273664. Its totient is φ = 10330614600.
The previous prime is 10335444103. The next prime is 10335444137. The reversal of 10335444131 is 13144453301.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10335444131 is a prime.
It is a super-2 number, since 2×103354441312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10335444094 and 10335444103.
It is not an unprimeable number, because it can be changed into a prime (10335444137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2411555 + ... + 2415836.
It is an arithmetic number, because the mean of its divisors is an integer number (2585068416).
Almost surely, 210335444131 is an apocalyptic number.
10335444131 is a deficient number, since it is larger than the sum of its proper divisors (4829533).
10335444131 is an equidigital number, since it uses as much as digits as its factorization.
10335444131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4829532.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 10335444131 its reverse (13144453301), we get a palindrome (23479897432).
The spelling of 10335444131 in words is "ten billion, three hundred thirty-five million, four hundred forty-four thousand, one hundred thirty-one".
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