Base | Representation |
---|---|
bin | 11110000110001010010… |
… | …11111111010010011011 |
3 | 10122212012020100111121221 |
4 | 33003011023333102123 |
5 | 113420314200433103 |
6 | 2111020440312511 |
7 | 134465654262412 |
oct | 17030513772233 |
9 | 3585166314557 |
10 | 1034100405403 |
11 | 3696177a121a |
12 | 1484ba172737 |
13 | 76691008510 |
14 | 3809d2a0479 |
15 | 1bd7534a1bd |
hex | f0c52ff49b |
1034100405403 has 16 divisors (see below), whose sum is σ = 1130408939296. Its totient is φ = 940190042880.
The previous prime is 1034100405397. The next prime is 1034100405449. The reversal of 1034100405403 is 3045040014301.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1034100405403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1034100405463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7352125 + ... + 7491457.
It is an arithmetic number, because the mean of its divisors is an integer number (70650558706).
Almost surely, 21034100405403 is an apocalyptic number.
1034100405403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1034100405403 is a deficient number, since it is larger than the sum of its proper divisors (96308533893).
1034100405403 is a wasteful number, since it uses less digits than its factorization.
1034100405403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147934.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1034100405403 its reverse (3045040014301), we get a palindrome (4079140419704).
The spelling of 1034100405403 in words is "one trillion, thirty-four billion, one hundred million, four hundred five thousand, four hundred three".
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