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10341112433 is a prime number
BaseRepresentation
bin10011010000110000…
…01101101001110001
3222200200121221102012
421220120031221301
5132134311044213
64430045532305
7514156001561
oct115030155161
928620557365
1010341112433
114427319913
122007274095
13c8a581252
14701598da1
15407cdd4a8
hex26860da71

10341112433 has 2 divisors, whose sum is σ = 10341112434. Its totient is φ = 10341112432.

The previous prime is 10341112399. The next prime is 10341112447. The reversal of 10341112433 is 33421114301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10278512689 + 62599744 = 101383^2 + 7912^2 .

It is an emirp because it is prime and its reverse (33421114301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10341112433 - 226 = 10274003569 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10341112399 and 10341112408.

It is not a weakly prime, because it can be changed into another prime (10341112493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170556216 + 5170556217.

It is an arithmetic number, because the mean of its divisors is an integer number (5170556217).

Almost surely, 210341112433 is an apocalyptic number.

It is an amenable number.

10341112433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10341112433 is an equidigital number, since it uses as much as digits as its factorization.

10341112433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 10341112433 its reverse (33421114301), we get a palindrome (43762226734).

The spelling of 10341112433 in words is "ten billion, three hundred forty-one million, one hundred twelve thousand, four hundred thirty-three".