Base | Representation |
---|---|
bin | 110000001001111001… |
… | …0001000110001000011 |
3 | 100212220220021110111100 |
4 | 1200103302020301003 |
5 | 3143241222002230 |
6 | 115301215145443 |
7 | 10320424030161 |
oct | 1402362106103 |
9 | 325826243440 |
10 | 103411125315 |
11 | 3a946980033 |
12 | 18060215283 |
13 | 99a042c3a4 |
14 | 50100c6231 |
15 | 2a5393d660 |
hex | 1813c88c43 |
103411125315 has 12 divisors (see below), whose sum is σ = 179245950624. Its totient is φ = 55152600144.
The previous prime is 103411125269. The next prime is 103411125353. The reversal of 103411125315 is 513521114301.
103411125315 is a `hidden beast` number, since 1 + 0 + 341 + 1 + 1 + 2 + 5 + 315 = 666.
It is not a de Polignac number, because 103411125315 - 27 = 103411125187 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1149012459 + ... + 1149012548.
It is an arithmetic number, because the mean of its divisors is an integer number (14937162552).
Almost surely, 2103411125315 is an apocalyptic number.
103411125315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
103411125315 is a deficient number, since it is larger than the sum of its proper divisors (75834825309).
103411125315 is a wasteful number, since it uses less digits than its factorization.
103411125315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2298025018 (or 2298025015 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
Adding to 103411125315 its reverse (513521114301), we get a palindrome (616932239616).
The spelling of 103411125315 in words is "one hundred three billion, four hundred eleven million, one hundred twenty-five thousand, three hundred fifteen".
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