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10341134144113 is a prime number
BaseRepresentation
bin1001011001111011101110…
…1000001001001001110001
31100121121021102022022022111
42112132323220021021301
52323412120320102423
633554352413405321
72115056641622233
oct226367350111161
940547242268274
1010341134144113
1133277176a4643
1211b0220a99841
135a021acb3676
1427a729308253
1512dee396660d
hex967bba09271

10341134144113 has 2 divisors, whose sum is σ = 10341134144114. Its totient is φ = 10341134144112.

The previous prime is 10341134144083. The next prime is 10341134144119. The reversal of 10341134144113 is 31144143114301.

It is a happy number.

10341134144113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9008744122849 + 1332390021264 = 3001457^2 + 1154292^2 .

It is a cyclic number.

It is not a de Polignac number, because 10341134144113 - 29 = 10341134143601 is a prime.

It is not a weakly prime, because it can be changed into another prime (10341134144119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170567072056 + 5170567072057.

It is an arithmetic number, because the mean of its divisors is an integer number (5170567072057).

Almost surely, 210341134144113 is an apocalyptic number.

It is an amenable number.

10341134144113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10341134144113 is an equidigital number, since it uses as much as digits as its factorization.

10341134144113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 10341134144113 its reverse (31144143114301), we get a palindrome (41485277258414).

The spelling of 10341134144113 in words is "ten trillion, three hundred forty-one billion, one hundred thirty-four million, one hundred forty-four thousand, one hundred thirteen".