Base | Representation |
---|---|
bin | 111101101000110… |
… | …111010011000001 |
3 | 2200001212212021212 |
4 | 331220313103001 |
5 | 4104213404213 |
6 | 250340455505 |
7 | 34424616131 |
oct | 7550672301 |
9 | 2601785255 |
10 | 1034122433 |
11 | 49080a543 |
12 | 24a3aa595 |
13 | 136326686 |
14 | 9b4b0ac1 |
15 | 60bc19a8 |
hex | 3da374c1 |
1034122433 has 2 divisors, whose sum is σ = 1034122434. Its totient is φ = 1034122432.
The previous prime is 1034122429. The next prime is 1034122451. The reversal of 1034122433 is 3342214301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 636199729 + 397922704 = 25223^2 + 19948^2 .
It is a cyclic number.
It is not a de Polignac number, because 1034122433 - 22 = 1034122429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1034122399 and 1034122408.
It is not a weakly prime, because it can be changed into another prime (1034122483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517061216 + 517061217.
It is an arithmetic number, because the mean of its divisors is an integer number (517061217).
Almost surely, 21034122433 is an apocalyptic number.
It is an amenable number.
1034122433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1034122433 is an equidigital number, since it uses as much as digits as its factorization.
1034122433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
The square root of 1034122433 is about 32157.7740678673. The cubic root of 1034122433 is about 1011.2471712214.
Adding to 1034122433 its reverse (3342214301), we get a palindrome (4376336734).
The spelling of 1034122433 in words is "one billion, thirty-four million, one hundred twenty-two thousand, four hundred thirty-three".
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