Search a number
-
+
103412410403 = 131789407713
BaseRepresentation
bin110000001001111011…
…1000010100000100011
3100212220222200202022012
41200103313002200203
53143242034113103
6115301302503135
710320440661611
oct1402367024043
9325828622265
10103412410403
113a947678595
1218060734aab
1399a078c2b3
14501033c6b1
152a53ae42d8
hex1813dc2823

103412410403 has 4 divisors (see below), whose sum is σ = 104201818248. Its totient is φ = 102623002560.

The previous prime is 103412410391. The next prime is 103412410447. The reversal of 103412410403 is 304014214301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103412410403 - 28 = 103412410147 is a prime.

It is a super-3 number, since 3×1034124104033 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103412410463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 394703726 + ... + 394703987.

It is an arithmetic number, because the mean of its divisors is an integer number (26050454562).

Almost surely, 2103412410403 is an apocalyptic number.

103412410403 is a deficient number, since it is larger than the sum of its proper divisors (789407845).

103412410403 is an equidigital number, since it uses as much as digits as its factorization.

103412410403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 789407844.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 103412410403 its reverse (304014214301), we get a palindrome (407426624704).

The spelling of 103412410403 in words is "one hundred three billion, four hundred twelve million, four hundred ten thousand, four hundred three".

Divisors: 1 131 789407713 103412410403