103414101131 has 4 divisors (see below), whose sum is σ = 112815383064. Its totient is φ = 94012819200.

The previous prime is 103414101103. The next prime is 103414101137. The reversal of 103414101131 is 131101414301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103414101131 - 2¹⁴ = 103414084747 is a prime.

It is a super-2 number, since 2×103414101131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103414101137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4700640950 + ... + 4700640971.

It is an arithmetic number, because the mean of its divisors is an integer number (28203845766).

Almost surely, 2^103414101131 is an apocalyptic number.

103414101131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

103414101131 is a deficient number, since it is larger than the sum of its proper divisors (9401281933).

103414101131 is an equidigital number, since it uses as much as digits as its factorization.

103414101131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9401281932.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 103414101131 its reverse (131101414301), we get a palindrome (234515515432).

The spelling of 103414101131 in words is "one hundred three billion, four hundred fourteen million, one hundred one thousand, one hundred thirty-one".