Base | Representation |
---|---|
bin | 1001011010000011110110… |
… | …0000100111111111000010 |
3 | 1100121210220021121101120201 |
4 | 2112200331200213333002 |
5 | 2323431101140230310 |
6 | 33555352534355414 |
7 | 2115164641446001 |
oct | 226407540477702 |
9 | 40553807541521 |
10 | 10343313211330 |
11 | 3328635727040 |
12 | 11b072a7bbb6a |
13 | 5a04a7596158 |
14 | 27a894896c38 |
15 | 12e0bedeae3a |
hex | 9683d827fc2 |
10343313211330 has 32 divisors (see below), whose sum is σ = 20311380555840. Its totient is φ = 3761042838720.
The previous prime is 10343313211313. The next prime is 10343313211333. The reversal of 10343313211330 is 3311231334301.
10343313211330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (10343313211333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 556381 + ... + 4582159.
It is an arithmetic number, because the mean of its divisors is an integer number (634730642370).
Almost surely, 210343313211330 is an apocalyptic number.
10343313211330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10343313211330 is a deficient number, since it is larger than the sum of its proper divisors (9968067344510).
10343313211330 is a wasteful number, since it uses less digits than its factorization.
10343313211330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4049154.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 10343313211330 its reverse (3311231334301), we get a palindrome (13654544545631).
The spelling of 10343313211330 in words is "ten trillion, three hundred forty-three billion, three hundred thirteen million, two hundred eleven thousand, three hundred thirty".
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