Base | Representation |
---|---|
bin | 10111100001001001100111… |
… | …001110111111000101101011 |
3 | 111120020002222222101021222211 |
4 | 113201021213032333011223 |
5 | 102024122024401411242 |
6 | 1003552305335425551 |
7 | 30533540331114205 |
oct | 2741114716770553 |
9 | 446202888337884 |
10 | 103433134403947 |
11 | 2aa58822969367 |
12 | b72604b5252b7 |
13 | 4593919b5b95a |
14 | 1b78294707775 |
15 | be57ee7c8317 |
hex | 5e12673bf16b |
103433134403947 has 2 divisors, whose sum is σ = 103433134403948. Its totient is φ = 103433134403946.
The previous prime is 103433134403881. The next prime is 103433134404079. The reversal of 103433134403947 is 749304431334301.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103433134403947 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 103433134403947.
It is not a weakly prime, because it can be changed into another prime (103433134403747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51716567201973 + 51716567201974.
It is an arithmetic number, because the mean of its divisors is an integer number (51716567201974).
Almost surely, 2103433134403947 is an apocalyptic number.
103433134403947 is a deficient number, since it is larger than the sum of its proper divisors (1).
103433134403947 is an equidigital number, since it uses as much as digits as its factorization.
103433134403947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3919104, while the sum is 49.
The spelling of 103433134403947 in words is "one hundred three trillion, four hundred thirty-three billion, one hundred thirty-four million, four hundred three thousand, nine hundred forty-seven".
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