Base | Representation |
---|---|
bin | 10111100001001001100111… |
… | …001110111111000111101111 |
3 | 111120020002222222101022011201 |
4 | 113201021213032333013233 |
5 | 102024122024401412304 |
6 | 1003552305335430331 |
7 | 30533540331114454 |
oct | 2741114716770757 |
9 | 446202888338151 |
10 | 103433134404079 |
11 | 2aa58822969477 |
12 | b72604b5253a7 |
13 | 4593919b5ba2c |
14 | 1b7829470782b |
15 | be57ee7c83a4 |
hex | 5e12673bf1ef |
103433134404079 has 2 divisors, whose sum is σ = 103433134404080. Its totient is φ = 103433134404078.
The previous prime is 103433134403947. The next prime is 103433134404101. The reversal of 103433134404079 is 970404431334301.
It is a strong prime.
It is an emirp because it is prime and its reverse (970404431334301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103433134404079 - 29 = 103433134403567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103433134405079) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51716567202039 + 51716567202040.
It is an arithmetic number, because the mean of its divisors is an integer number (51716567202040).
Almost surely, 2103433134404079 is an apocalyptic number.
103433134404079 is a deficient number, since it is larger than the sum of its proper divisors (1).
103433134404079 is an equidigital number, since it uses as much as digits as its factorization.
103433134404079 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 46.
The spelling of 103433134404079 in words is "one hundred three trillion, four hundred thirty-three billion, one hundred thirty-four million, four hundred four thousand, seventy-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •