103433134404133 has 8 divisors (see below), whose sum is σ = 103620213553752. Its totient is φ = 103246060210176.

The previous prime is 103433134404121. The next prime is 103433134404143. The reversal of 103433134404133 is 331404431334301.

It can be written as a sum of positive squares in 4 ways, for example, as 3740537798209 + 99692596605924 = 1934047^2 + 9984618^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 103433134404133 - 2⁵ = 103433134404101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103433134404092 and 103433134404101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103433134404113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41899041 + ... + 44298937.

It is an arithmetic number, because the mean of its divisors is an integer number (12952526694219).

Almost surely, 2^{103433134404133} is an apocalyptic number.

It is an amenable number.

103433134404133 is a deficient number, since it is larger than the sum of its proper divisors (187079149619).

103433134404133 is an equidigital number, since it uses as much as digits as its factorization.

103433134404133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2477831.

The product of its (nonzero) digits is 186624, while the sum is 37.

Adding to 103433134404133 its reverse (331404431334301), we get a palindrome (434837565738434).

The spelling of 103433134404133 in words is "one hundred three trillion, four hundred thirty-three billion, one hundred thirty-four million, four hundred four thousand, one hundred thirty-three".