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1034334013213 is a prime number
BaseRepresentation
bin11110000110100110001…
…11001000011100011101
310122212210111221000022001
433003103013020130131
5113421304001410323
62111055543322301
7134504522022634
oct17032307103435
93585714830261
101034334013213
11369727649226
12148564450391
13766ca52b9a7
14380c231051b
151bd8aae23ad
hexf0d31c871d

1034334013213 has 2 divisors, whose sum is σ = 1034334013214. Its totient is φ = 1034334013212.

The previous prime is 1034334013183. The next prime is 1034334013291. The reversal of 1034334013213 is 3123104334301.

1034334013213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1016624525284 + 17709487929 = 1008278^2 + 133077^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1034334013213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1034334013513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517167006606 + 517167006607.

It is an arithmetic number, because the mean of its divisors is an integer number (517167006607).

Almost surely, 21034334013213 is an apocalyptic number.

It is an amenable number.

1034334013213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1034334013213 is an equidigital number, since it uses as much as digits as its factorization.

1034334013213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 1034334013213 its reverse (3123104334301), we get a palindrome (4157438347514).

The spelling of 1034334013213 in words is "one trillion, thirty-four billion, three hundred thirty-four million, thirteen thousand, two hundred thirteen".