Base | Representation |
---|---|
bin | 11110000110100110010… |
… | …00010001111011100011 |
3 | 10122212210112111022012010 |
4 | 33003103020101323203 |
5 | 113421304041023321 |
6 | 2111055554004003 |
7 | 134504524415322 |
oct | 17032310217343 |
9 | 3585715438163 |
10 | 1034334314211 |
11 | 369727834390 |
12 | 148564576603 |
13 | 766ca6059b3 |
14 | 380c238c0b9 |
15 | 1bd8ab51676 |
hex | f0d3211ee3 |
1034334314211 has 16 divisors (see below), whose sum is σ = 1539474330240. Its totient is φ = 612290925120.
The previous prime is 1034334314203. The next prime is 1034334314291. The reversal of 1034334314211 is 1124134334301.
1034334314211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 1034334314211 - 23 = 1034334314203 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1034334314291) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 364457466 + ... + 364460303.
It is an arithmetic number, because the mean of its divisors is an integer number (96217145640).
Almost surely, 21034334314211 is an apocalyptic number.
1034334314211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1034334314211 is a deficient number, since it is larger than the sum of its proper divisors (505140016029).
1034334314211 is a wasteful number, since it uses less digits than its factorization.
1034334314211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 728917826.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 1034334314211 its reverse (1124134334301), we get a palindrome (2158468648512).
The spelling of 1034334314211 in words is "one trillion, thirty-four billion, three hundred thirty-four million, three hundred fourteen thousand, two hundred eleven".
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