Base | Representation |
---|---|
bin | 1001011010000100010010… |
… | …1010010110010111001111 |
3 | 1100121211012122101111121101 |
4 | 2112201010222112113033 |
5 | 2323431322344413403 |
6 | 33555412502243531 |
7 | 2115200626365262 |
oct | 226410452262717 |
9 | 40554178344541 |
10 | 10343433201103 |
11 | 3328697431142 |
12 | 11b0762a265a7 |
13 | 5a04c63b8512 |
14 | 27a8a67accd9 |
15 | 12e0ca6ed71d |
hex | 96844a965cf |
10343433201103 has 2 divisors, whose sum is σ = 10343433201104. Its totient is φ = 10343433201102.
The previous prime is 10343433201097. The next prime is 10343433201221. The reversal of 10343433201103 is 30110233434301.
It is a weak prime.
It is an emirp because it is prime and its reverse (30110233434301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10343433201103 is a prime.
It is a super-2 number, since 2×103434332011032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10343433201503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5171716600551 + 5171716600552.
It is an arithmetic number, because the mean of its divisors is an integer number (5171716600552).
Almost surely, 210343433201103 is an apocalyptic number.
10343433201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
10343433201103 is an equidigital number, since it uses as much as digits as its factorization.
10343433201103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 10343433201103 its reverse (30110233434301), we get a palindrome (40453666635404).
The spelling of 10343433201103 in words is "ten trillion, three hundred forty-three billion, four hundred thirty-three million, two hundred one thousand, one hundred three".
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