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103439985597017 is a prime number
BaseRepresentation
bin10111100001001111111111…
…100110001101101001011001
3111120020202200110002222001022
4113201033333212031221121
5102024230042303101032
61003555401240332225
730534202162233056
oct2741177746155131
9446222613088038
10103439985597017
112aa607192160a3
12b727441a74075
13459446c392a54
141b787445aa02d
15be5aa0eeb512
hex5e13ff98da59

103439985597017 has 2 divisors, whose sum is σ = 103439985597018. Its totient is φ = 103439985597016.

The previous prime is 103439985596999. The next prime is 103439985597019. The reversal of 103439985597017 is 710795589934301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68601943151641 + 34838042445376 = 8282629^2 + 5902376^2 .

It is a cyclic number.

It is not a de Polignac number, because 103439985597017 - 212 = 103439985592921 is a prime.

It is a super-2 number, since 2×1034399855970172 (a number of 29 digits) contains 22 as substring.

Together with 103439985597019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (103439985597019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51719992798508 + 51719992798509.

It is an arithmetic number, because the mean of its divisors is an integer number (51719992798509).

Almost surely, 2103439985597017 is an apocalyptic number.

It is an amenable number.

103439985597017 is a deficient number, since it is larger than the sum of its proper divisors (1).

103439985597017 is an equidigital number, since it uses as much as digits as its factorization.

103439985597017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 257191200, while the sum is 71.

The spelling of 103439985597017 in words is "one hundred three trillion, four hundred thirty-nine billion, nine hundred eighty-five million, five hundred ninety-seven thousand, seventeen".