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10344311101 = 67154392703
BaseRepresentation
bin10011010001001000…
…11010100100111101
3222200220122110011101
421220210122210331
5132141120423401
64430242253101
7514225123255
oct115044324475
928626573141
1010344311101
114429104043
122008357191
13c8b131157
14701b8c965
15408221101
hex26891a93d

10344311101 has 4 divisors (see below), whose sum is σ = 10498703872. Its totient is φ = 10189918332.

The previous prime is 10344311099. The next prime is 10344311119. The reversal of 10344311101 is 10111344301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10111344301 = 12413814577.

It is a cyclic number.

It is not a de Polignac number, because 10344311101 - 21 = 10344311099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10344311171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77196285 + ... + 77196418.

It is an arithmetic number, because the mean of its divisors is an integer number (2624675968).

Almost surely, 210344311101 is an apocalyptic number.

It is an amenable number.

10344311101 is a deficient number, since it is larger than the sum of its proper divisors (154392771).

10344311101 is an equidigital number, since it uses as much as digits as its factorization.

10344311101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154392770.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10344311101 its reverse (10111344301), we get a palindrome (20455655402).

The spelling of 10344311101 in words is "ten billion, three hundred forty-four million, three hundred eleven thousand, one hundred one".

Divisors: 1 67 154392703 10344311101