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1034440202413 is a prime number
BaseRepresentation
bin11110000110110010111…
…00001101100010101101
310122220001220201222111101
433003121130031202231
5113422013142434123
62111114255323101
7134510251433302
oct17033134154255
93586056658441
101034440202413
113697815877a2
12148593b20491
137671652b637
14380d24730a9
151bd950baaad
hexf0d970d8ad

1034440202413 has 2 divisors, whose sum is σ = 1034440202414. Its totient is φ = 1034440202412.

The previous prime is 1034440202381. The next prime is 1034440202437. The reversal of 1034440202413 is 3142020444301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 860920468164 + 173519734249 = 927858^2 + 416557^2 .

It is an emirp because it is prime and its reverse (3142020444301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1034440202413 - 25 = 1034440202381 is a prime.

It is a super-2 number, since 2×10344402024132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1034440202473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517220101206 + 517220101207.

It is an arithmetic number, because the mean of its divisors is an integer number (517220101207).

Almost surely, 21034440202413 is an apocalyptic number.

It is an amenable number.

1034440202413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1034440202413 is an equidigital number, since it uses as much as digits as its factorization.

1034440202413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 1034440202413 its reverse (3142020444301), we get a palindrome (4176460646714).

The spelling of 1034440202413 in words is "one trillion, thirty-four billion, four hundred forty million, two hundred two thousand, four hundred thirteen".