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103445343321 = 334481781107
BaseRepresentation
bin110000001010111010…
…0101010110001011001
3100220000021122220202220
41200111310222301121
53143324001441241
6115304440414253
710321320624135
oct1402564526131
9326007586686
10103445343321
113a964221581
121806b777389
1399a7550228
1450148723c5
152a5694c166
hex1815d2ac59

103445343321 has 4 divisors (see below), whose sum is σ = 137927124432. Its totient is φ = 68963562212.

The previous prime is 103445343259. The next prime is 103445343347. The reversal of 103445343321 is 123343544301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103445343321 - 29 = 103445342809 is a prime.

It is not an unprimeable number, because it can be changed into a prime (103445343371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17240890551 + ... + 17240890556.

It is an arithmetic number, because the mean of its divisors is an integer number (34481781108).

Almost surely, 2103445343321 is an apocalyptic number.

It is an amenable number.

103445343321 is a deficient number, since it is larger than the sum of its proper divisors (34481781111).

103445343321 is an equidigital number, since it uses as much as digits as its factorization.

103445343321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34481781110.

The product of its (nonzero) digits is 51840, while the sum is 33.

Adding to 103445343321 its reverse (123343544301), we get a palindrome (226788887622).

The spelling of 103445343321 in words is "one hundred three billion, four hundred forty-five million, three hundred forty-three thousand, three hundred twenty-one".

Divisors: 1 3 34481781107 103445343321