Base | Representation |
---|---|
bin | 11110001000000110010… |
… | …11010000110101110111 |
3 | 10122221212201021211111211 |
4 | 33010003023100311313 |
5 | 113424431420340201 |
6 | 2111311551142251 |
7 | 134533513150153 |
oct | 17040313206567 |
9 | 3587781254454 |
10 | 1035140402551 |
11 | 36a0008534a2 |
12 | 14874a514987 |
13 | 767c860ab48 |
14 | 3815b460063 |
15 | 1bdd67cc651 |
hex | f1032d0d77 |
1035140402551 has 2 divisors, whose sum is σ = 1035140402552. Its totient is φ = 1035140402550.
The previous prime is 1035140402539. The next prime is 1035140402573. The reversal of 1035140402551 is 1552040415301.
1035140402551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1035140402551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1035140402591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517570201275 + 517570201276.
It is an arithmetic number, because the mean of its divisors is an integer number (517570201276).
Almost surely, 21035140402551 is an apocalyptic number.
1035140402551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1035140402551 is an equidigital number, since it uses as much as digits as its factorization.
1035140402551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 1035140402551 its reverse (1552040415301), we get a palindrome (2587180817852).
The spelling of 1035140402551 in words is "one trillion, thirty-five billion, one hundred forty million, four hundred two thousand, five hundred fifty-one".
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