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10352434433 = 11941130403
BaseRepresentation
bin10011010010000110…
…11001110100000001
3222201110221011021112
421221003121310001
5132200210400213
64431132333105
7514354145405
oct115103316401
928643834245
1010352434433
114432752240
12200b014195
13c8ca16763
14702ca5105
15408cc7ea8
hex2690d9d01

10352434433 has 4 divisors (see below), whose sum is σ = 11293564848. Its totient is φ = 9411304020.

The previous prime is 10352434423. The next prime is 10352434453. The reversal of 10352434433 is 33443425301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10352434433 - 214 = 10352418049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10352434433.

It is not an unprimeable number, because it can be changed into a prime (10352434423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 470565191 + ... + 470565212.

It is an arithmetic number, because the mean of its divisors is an integer number (2823391212).

Almost surely, 210352434433 is an apocalyptic number.

It is an amenable number.

10352434433 is a deficient number, since it is larger than the sum of its proper divisors (941130415).

10352434433 is an equidigital number, since it uses as much as digits as its factorization.

10352434433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 941130414.

The product of its (nonzero) digits is 51840, while the sum is 32.

Adding to 10352434433 its reverse (33443425301), we get a palindrome (43795859734).

The spelling of 10352434433 in words is "ten billion, three hundred fifty-two million, four hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 11 941130403 10352434433