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10353113 = 47220279
BaseRepresentation
bin100111011111…
…100111011001
3201110222210122
4213133213121
510122244423
61005523025
7154000001
oct47374731
921428718
1010353113
1159314a1
123573475
1321b6504
141537001
15d978c8
hex9df9d9

10353113 has 4 divisors (see below), whose sum is σ = 10573440. Its totient is φ = 10132788.

The previous prime is 10353107. The next prime is 10353121. The reversal of 10353113 is 31135301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10353113 - 24 = 10353097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10353091 and 10353100.

It is not an unprimeable number, because it can be changed into a prime (10353193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110093 + ... + 110186.

It is an arithmetic number, because the mean of its divisors is an integer number (2643360).

Almost surely, 210353113 is an apocalyptic number.

It is an amenable number.

10353113 is a deficient number, since it is larger than the sum of its proper divisors (220327).

10353113 is an equidigital number, since it uses as much as digits as its factorization.

10353113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 220326.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 10353113 is about 3217.6253666330. The cubic root of 10353113 is about 217.9500558930.

Adding to 10353113 its reverse (31135301), we get a palindrome (41488414).

The spelling of 10353113 in words is "ten million, three hundred fifty-three thousand, one hundred thirteen".

Divisors: 1 47 220279 10353113