10354111211 has 2 divisors, whose sum is σ = 10354111212. Its totient is φ = 10354111210.

The previous prime is 10354111109. The next prime is 10354111213. The reversal of 10354111211 is 11211145301.

10354111211 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10354111211 is a prime.

It is a super-3 number, since 3×10354111211³ (a number of 31 digits) contains 333 as substring.

Together with 10354111213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10354111213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177055605 + 5177055606.

It is an arithmetic number, because the mean of its divisors is an integer number (5177055606).

Almost surely, 2^10354111211 is an apocalyptic number.

10354111211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10354111211 is an equidigital number, since it uses as much as digits as its factorization.

10354111211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 10354111211 its reverse (11211145301), we get a palindrome (21565256512).

The spelling of 10354111211 in words is "ten billion, three hundred fifty-four million, one hundred eleven thousand, two hundred eleven".