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103544030143 = 1943126736879
BaseRepresentation
bin110000001101110110…
…1001000001110111111
3100220021011100201122101
41200123231020032333
53144024232431033
6115322323525531
710323626506621
oct1403355101677
9326234321571
10103544030143
113aa049a6434
12180988298a7
1399c1b240b8
145023a00c11
152a6044297d
hex181bb483bf

103544030143 has 8 divisors (see below), whose sum is σ = 111528454400. Its totient is φ = 95813079768.

The previous prime is 103544030087. The next prime is 103544030167. The reversal of 103544030143 is 341030445301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 103544030143 - 213 = 103544021951 is a prime.

It is a super-3 number, since 3×1035440301433 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103544030243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63367623 + ... + 63369256.

It is an arithmetic number, because the mean of its divisors is an integer number (13941056800).

Almost surely, 2103544030143 is an apocalyptic number.

103544030143 is a deficient number, since it is larger than the sum of its proper divisors (7984424257).

103544030143 is a wasteful number, since it uses less digits than its factorization.

103544030143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126736941.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 103544030143 its reverse (341030445301), we get a palindrome (444574475444).

The spelling of 103544030143 in words is "one hundred three billion, five hundred forty-four million, thirty thousand, one hundred forty-three".

Divisors: 1 19 43 817 126736879 2408000701 5449685797 103544030143