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10354422257 is a prime number
BaseRepresentation
bin10011010010010101…
…11111000111110001
3222201121200011001122
421221022333013301
5132201213003012
64431243112025
7514410064664
oct115112770761
928647604048
1010354422257
11443388a773
12200b812615
13c9026149a
147032616db
1540906be72
hex2692bf1f1

10354422257 has 2 divisors, whose sum is σ = 10354422258. Its totient is φ = 10354422256.

The previous prime is 10354422223. The next prime is 10354422319. The reversal of 10354422257 is 75222445301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7725706816 + 2628715441 = 87896^2 + 51271^2 .

It is a cyclic number.

It is not a de Polignac number, because 10354422257 - 212 = 10354418161 is a prime.

It is a super-3 number, since 3×103544222573 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10354422157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177211128 + 5177211129.

It is an arithmetic number, because the mean of its divisors is an integer number (5177211129).

Almost surely, 210354422257 is an apocalyptic number.

It is an amenable number.

10354422257 is a deficient number, since it is larger than the sum of its proper divisors (1).

10354422257 is an equidigital number, since it uses as much as digits as its factorization.

10354422257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 35.

Adding to 10354422257 its reverse (75222445301), we get a palindrome (85576867558).

The spelling of 10354422257 in words is "ten billion, three hundred fifty-four million, four hundred twenty-two thousand, two hundred fifty-seven".