4431243112025 has 12 divisors (see below), whose sum is σ = 5494814026284. Its totient is φ = 3544947672000.

The previous prime is 4431243111989. The next prime is 4431243112039. The reversal of 4431243112025 is 5202113421344.

It can be written as a sum of positive squares in 6 ways, for example, as 5382276496 + 4425860835529 = 73364^2 + 2103773^2 .

It is not a de Polignac number, because 4431243112025 - 2¹⁴ = 4431243095641 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4431243111982 and 4431243112000.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 827255 + ... + 3089795.

It is an arithmetic number, because the mean of its divisors is an integer number (457901168857).

Almost surely, 2^{4431243112025} is an apocalyptic number.

It is an amenable number.

4431243112025 is a deficient number, since it is larger than the sum of its proper divisors (1063570914259).

4431243112025 is a wasteful number, since it uses less digits than its factorization.

4431243112025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2340892 (or 2340887 counting only the distinct ones).

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 4431243112025 its reverse (5202113421344), we get a palindrome (9633356533369).

The spelling of 4431243112025 in words is "four trillion, four hundred thirty-one billion, two hundred forty-three million, one hundred twelve thousand, twenty-five".