Base | Representation |
---|---|
bin | 10011010010010110… |
… | …00100011101100011 |
3 | 222201121201021001210 |
4 | 21221023010131203 |
5 | 132201214203011 |
6 | 4431243401203 |
7 | 514410215523 |
oct | 115113043543 |
9 | 28647637053 |
10 | 10354444131 |
11 | 44338a5149 |
12 | 200b823203 |
13 | c9026b425 |
14 | 703269683 |
15 | 4090736a6 |
hex | 2692c4763 |
10354444131 has 4 divisors (see below), whose sum is σ = 13805925512. Its totient is φ = 6902962752.
The previous prime is 10354444123. The next prime is 10354444183. The reversal of 10354444131 is 13144445301.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 10354444131 - 23 = 10354444123 is a prime.
It is a super-3 number, since 3×103544441313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10354444531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1725740686 + ... + 1725740691.
It is an arithmetic number, because the mean of its divisors is an integer number (3451481378).
Almost surely, 210354444131 is an apocalyptic number.
10354444131 is a deficient number, since it is larger than the sum of its proper divisors (3451481381).
10354444131 is an equidigital number, since it uses as much as digits as its factorization.
10354444131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3451481380.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 10354444131 its reverse (13144445301), we get a palindrome (23498889432).
The spelling of 10354444131 in words is "ten billion, three hundred fifty-four million, four hundred forty-four thousand, one hundred thirty-one".
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