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103550569441 = 119413688131
BaseRepresentation
bin110000001110000011…
…0000100101111100001
3100220021121122221212121
41200130012010233201
53144032421210231
6115323120024241
710324036213624
oct1403406045741
9326247587777
10103550569441
113aa08662510
121809aa62081
1399c32a36c7
145024823dbb
152a60cd5311
hex181c184be1

103550569441 has 4 divisors (see below), whose sum is σ = 112964257584. Its totient is φ = 94136881300.

The previous prime is 103550569399. The next prime is 103550569453. The reversal of 103550569441 is 144965055301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 103550569441 - 213 = 103550561249 is a prime.

It is a super-3 number, since 3×1035505694413 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103550569471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4706844055 + ... + 4706844076.

It is an arithmetic number, because the mean of its divisors is an integer number (28241064396).

Almost surely, 2103550569441 is an apocalyptic number.

103550569441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

103550569441 is a deficient number, since it is larger than the sum of its proper divisors (9413688143).

103550569441 is an equidigital number, since it uses as much as digits as its factorization.

103550569441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9413688142.

The product of its (nonzero) digits is 324000, while the sum is 43.

The spelling of 103550569441 in words is "one hundred three billion, five hundred fifty million, five hundred sixty-nine thousand, four hundred forty-one".

Divisors: 1 11 9413688131 103550569441