Base | Representation |
---|---|
bin | 10011010010011100… |
… | …00101011001001101 |
3 | 222201200012102002022 |
4 | 21221032011121031 |
5 | 132201420000011 |
6 | 4431312335525 |
7 | 514420016462 |
oct | 115116053115 |
9 | 28650172068 |
10 | 10355234381 |
11 | 4434294948 |
12 | 200bb445a5 |
13 | c9048702b |
14 | 7033d3669 |
15 | 40917c8db |
hex | 26938564d |
10355234381 has 2 divisors, whose sum is σ = 10355234382. Its totient is φ = 10355234380.
The previous prime is 10355234377. The next prime is 10355234411. The reversal of 10355234381 is 18343255301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7240478281 + 3114756100 = 85091^2 + 55810^2 .
It is a cyclic number.
It is not a de Polignac number, because 10355234381 - 22 = 10355234377 is a prime.
It is a super-3 number, since 3×103552343813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10355234311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177617190 + 5177617191.
It is an arithmetic number, because the mean of its divisors is an integer number (5177617191).
Almost surely, 210355234381 is an apocalyptic number.
It is an amenable number.
10355234381 is a deficient number, since it is larger than the sum of its proper divisors (1).
10355234381 is an equidigital number, since it uses as much as digits as its factorization.
10355234381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 10355234381 its reverse (18343255301), we get a palindrome (28698489682).
The spelling of 10355234381 in words is "ten billion, three hundred fifty-five million, two hundred thirty-four thousand, three hundred eighty-one".
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