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1039429871531 is a prime number
BaseRepresentation
bin11110010000000101101…
…10010010011110101011
310200100221122200102202022
433020002312102132223
5114012223021342111
62113301341255055
7135045020062502
oct17100266223653
93610848612668
101039429871531
11370902078a87
12149546b6448b
13770301b0b7c
1438447005839
151c0881812db
hexf202d927ab

1039429871531 has 2 divisors, whose sum is σ = 1039429871532. Its totient is φ = 1039429871530.

The previous prime is 1039429871521. The next prime is 1039429871533. The reversal of 1039429871531 is 1351789249301.

1039429871531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1039429871531 is a prime.

It is a super-2 number, since 2×10394298715312 (a number of 25 digits) contains 22 as substring.

Together with 1039429871533, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1039429871533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 519714935765 + 519714935766.

It is an arithmetic number, because the mean of its divisors is an integer number (519714935766).

Almost surely, 21039429871531 is an apocalyptic number.

1039429871531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1039429871531 is an equidigital number, since it uses as much as digits as its factorization.

1039429871531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 53.

The spelling of 1039429871531 in words is "one trillion, thirty-nine billion, four hundred twenty-nine million, eight hundred seventy-one thousand, five hundred thirty-one".