Base | Representation |
---|---|
bin | 110000011011011110… |
… | …1100110001110110001 |
3 | 100221110000212002001120 |
4 | 1200312331212032301 |
5 | 3200443320112040 |
6 | 115435541252453 |
7 | 10341151510614 |
oct | 1406675461661 |
9 | 327400762046 |
10 | 104001332145 |
11 | 4011a04a177 |
12 | 181a5a04129 |
13 | 9a657a95b9 |
14 | 506864017b |
15 | 2a8a6747d0 |
hex | 1836f663b1 |
104001332145 has 16 divisors (see below), whose sum is σ = 168745825152. Its totient is φ = 54686145920.
The previous prime is 104001332117. The next prime is 104001332179. The reversal of 104001332145 is 541233100401.
It is a happy number.
It is not a de Polignac number, because 104001332145 - 213 = 104001323953 is a prime.
It is a super-3 number, since 3×1040013321453 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48825852 + ... + 48827981.
It is an arithmetic number, because the mean of its divisors is an integer number (10546614072).
Almost surely, 2104001332145 is an apocalyptic number.
104001332145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
104001332145 is a deficient number, since it is larger than the sum of its proper divisors (64744493007).
104001332145 is an equidigital number, since it uses as much as digits as its factorization.
104001332145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97653912.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 104001332145 its reverse (541233100401), we get a palindrome (645234432546).
The spelling of 104001332145 in words is "one hundred four billion, one million, three hundred thirty-two thousand, one hundred forty-five".
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