1040112132131 has 2 divisors, whose sum is σ = 1040112132132. Its totient is φ = 1040112132130.

The previous prime is 1040112132121. The next prime is 1040112132209. The reversal of 1040112132131 is 1312312110401.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1040112132131 is a prime.

It is a super-3 number, since 3×1040112132131³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1040112132121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520056066065 + 520056066066.

It is an arithmetic number, because the mean of its divisors is an integer number (520056066066).

Almost surely, 2^{1040112132131} is an apocalyptic number.

1040112132131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040112132131 is an equidigital number, since it uses as much as digits as its factorization.

1040112132131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1040112132131 its reverse (1312312110401), we get a palindrome (2352424242532).

The spelling of 1040112132131 in words is "one trillion, forty billion, one hundred twelve million, one hundred thirty-two thousand, one hundred thirty-one".