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1040122305433 is a prime number
BaseRepresentation
bin11110010001011000001…
…11101101101110011001
310200102201220121201111101
433020230013231232121
5114020132302233213
62113454154431401
7135101125502311
oct17105407555631
93612656551441
101040122305433
11371127a1a902
121496baa32561
13771107a1483
14384b0d70441
151c0c8d5bbdd
hexf22c1edb99

1040122305433 has 2 divisors, whose sum is σ = 1040122305434. Its totient is φ = 1040122305432.

The previous prime is 1040122305421. The next prime is 1040122305463. The reversal of 1040122305433 is 3345032210401.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 592918480144 + 447203825289 = 770012^2 + 668733^2 .

It is a cyclic number.

It is not a de Polignac number, because 1040122305433 - 25 = 1040122305401 is a prime.

It is not a weakly prime, because it can be changed into another prime (1040122305463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520061152716 + 520061152717.

It is an arithmetic number, because the mean of its divisors is an integer number (520061152717).

Almost surely, 21040122305433 is an apocalyptic number.

It is an amenable number.

1040122305433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040122305433 is an equidigital number, since it uses as much as digits as its factorization.

1040122305433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 1040122305433 its reverse (3345032210401), we get a palindrome (4385154515834).

The spelling of 1040122305433 in words is "one trillion, forty billion, one hundred twenty-two million, three hundred five thousand, four hundred thirty-three".