1040123151131 has 4 divisors (see below), whose sum is σ = 1051809928200. Its totient is φ = 1028436374064.

The previous prime is 1040123151047. The next prime is 1040123151157. The reversal of 1040123151131 is 1311513210401.

1040123151131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1040123151131 is a prime.

It is a super-2 number, since 2×1040123151131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1040123151097 and 1040123151106.

It is not an unprimeable number, because it can be changed into a prime (1040123151161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5843388401 + ... + 5843388578.

It is an arithmetic number, because the mean of its divisors is an integer number (262952482050).

Almost surely, 2^{1040123151131} is an apocalyptic number.

1040123151131 is a deficient number, since it is larger than the sum of its proper divisors (11686777069).

1040123151131 is an equidigital number, since it uses as much as digits as its factorization.

1040123151131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11686777068.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 1040123151131 its reverse (1311513210401), we get a palindrome (2351636361532).

The spelling of 1040123151131 in words is "one trillion, forty billion, one hundred twenty-three million, one hundred fifty-one thousand, one hundred thirty-one".