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10401241 = 47221303
BaseRepresentation
bin100111101011…
…010111011001
3201120102211011
4213223113121
510130314431
61010533521
7154260214
oct47532731
921512734
1010401241
115964674
1235972a1
1322023a6
14154a77b
15da6cb1
hex9eb5d9

10401241 has 4 divisors (see below), whose sum is σ = 10622592. Its totient is φ = 10179892.

The previous prime is 10401239. The next prime is 10401253. The reversal of 10401241 is 14210401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14210401 = 44931649.

It is a cyclic number.

It is not a de Polignac number, because 10401241 - 21 = 10401239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10401271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110605 + ... + 110698.

It is an arithmetic number, because the mean of its divisors is an integer number (2655648).

Almost surely, 210401241 is an apocalyptic number.

It is an amenable number.

10401241 is a deficient number, since it is larger than the sum of its proper divisors (221351).

10401241 is an equidigital number, since it uses as much as digits as its factorization.

10401241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221350.

The product of its (nonzero) digits is 32, while the sum is 13.

The square root of 10401241 is about 3225.0955024619. The cubic root of 10401241 is about 218.2872584372.

Adding to 10401241 its reverse (14210401), we get a palindrome (24611642).

The spelling of 10401241 in words is "ten million, four hundred one thousand, two hundred forty-one".

Divisors: 1 47 221303 10401241