Base | Representation |
---|---|
bin | 110000011011110101… |
… | …0001110011111110101 |
3 | 100221110211212110102210 |
4 | 1200313222032133311 |
5 | 3201004314001123 |
6 | 115441040124033 |
7 | 10341353115354 |
oct | 1406752163765 |
9 | 327424773383 |
10 | 104013031413 |
11 | 4012570aa95 |
12 | 181a9906619 |
13 | 9a68044745 |
14 | 506a00799b |
15 | 2a8b6d5e93 |
hex | 1837a8e7f5 |
104013031413 has 4 divisors (see below), whose sum is σ = 138684041888. Its totient is φ = 69342020940.
The previous prime is 104013031379. The next prime is 104013031427. The reversal of 104013031413 is 314130310401.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 104013031413 - 236 = 35293554677 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 104013031413.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (104013011413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17335505233 + ... + 17335505238.
It is an arithmetic number, because the mean of its divisors is an integer number (34671010472).
Almost surely, 2104013031413 is an apocalyptic number.
It is an amenable number.
104013031413 is a deficient number, since it is larger than the sum of its proper divisors (34671010475).
104013031413 is an equidigital number, since it uses as much as digits as its factorization.
104013031413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34671010474.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 104013031413 its reverse (314130310401), we get a palindrome (418143341814).
The spelling of 104013031413 in words is "one hundred four billion, thirteen million, thirty-one thousand, four hundred thirteen".
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