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104013031413 = 334671010471
BaseRepresentation
bin110000011011110101…
…0001110011111110101
3100221110211212110102210
41200313222032133311
53201004314001123
6115441040124033
710341353115354
oct1406752163765
9327424773383
10104013031413
114012570aa95
12181a9906619
139a68044745
14506a00799b
152a8b6d5e93
hex1837a8e7f5

104013031413 has 4 divisors (see below), whose sum is σ = 138684041888. Its totient is φ = 69342020940.

The previous prime is 104013031379. The next prime is 104013031427. The reversal of 104013031413 is 314130310401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 104013031413 - 236 = 35293554677 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 104013031413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (104013011413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17335505233 + ... + 17335505238.

It is an arithmetic number, because the mean of its divisors is an integer number (34671010472).

Almost surely, 2104013031413 is an apocalyptic number.

It is an amenable number.

104013031413 is a deficient number, since it is larger than the sum of its proper divisors (34671010475).

104013031413 is an equidigital number, since it uses as much as digits as its factorization.

104013031413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34671010474.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 104013031413 its reverse (314130310401), we get a palindrome (418143341814).

The spelling of 104013031413 in words is "one hundred four billion, thirteen million, thirty-one thousand, four hundred thirteen".

Divisors: 1 3 34671010471 104013031413