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104013142403 = 591762934617
BaseRepresentation
bin110000011011110101…
…0101001100110000011
3100221110212002002200112
41200313222221212003
53201004331024103
6115441042341535
710341354060062
oct1406752514603
9327425062615
10104013142403
1140125786415
12181a995a8ab
139a68083111
14506a0361d9
152a8b708cd8
hex1837aa9983

104013142403 has 4 divisors (see below), whose sum is σ = 105776077080. Its totient is φ = 102250207728.

The previous prime is 104013142361. The next prime is 104013142421. The reversal of 104013142403 is 304241310401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 104013142403 - 218 = 104012880259 is a prime.

It is a super-2 number, since 2×1040131424032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (104013142483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 881467250 + ... + 881467367.

It is an arithmetic number, because the mean of its divisors is an integer number (26444019270).

Almost surely, 2104013142403 is an apocalyptic number.

104013142403 is a deficient number, since it is larger than the sum of its proper divisors (1762934677).

104013142403 is an equidigital number, since it uses as much as digits as its factorization.

104013142403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1762934676.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 104013142403 its reverse (304241310401), we get a palindrome (408254452804).

The spelling of 104013142403 in words is "one hundred four billion, thirteen million, one hundred forty-two thousand, four hundred three".

Divisors: 1 59 1762934617 104013142403