Base | Representation |
---|---|
bin | 1001011101011100011001… |
… | …1100010100001111110111 |
3 | 1100211100221121002002211201 |
4 | 2113113012130110033313 |
5 | 2330404124423312401 |
6 | 34042205151313331 |
7 | 2122323335605024 |
oct | 227270634241767 |
9 | 40740847062751 |
10 | 10401445135351 |
11 | 3350256682a56 |
12 | 11bba52b1b847 |
13 | 5a5b0ccb942a |
14 | 27d60b1d254b |
15 | 130873649b01 |
hex | 975c67143f7 |
10401445135351 has 2 divisors, whose sum is σ = 10401445135352. Its totient is φ = 10401445135350.
The previous prime is 10401445135321. The next prime is 10401445135427. The reversal of 10401445135351 is 15353154410401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10401445135351 - 213 = 10401445127159 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10401445135351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10401445135321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200722567675 + 5200722567676.
It is an arithmetic number, because the mean of its divisors is an integer number (5200722567676).
Almost surely, 210401445135351 is an apocalyptic number.
10401445135351 is a deficient number, since it is larger than the sum of its proper divisors (1).
10401445135351 is an equidigital number, since it uses as much as digits as its factorization.
10401445135351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 10401445135351 its reverse (15353154410401), we get a palindrome (25754599545752).
The spelling of 10401445135351 in words is "ten trillion, four hundred one billion, four hundred forty-five million, one hundred thirty-five thousand, three hundred fifty-one".
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