Base | Representation |
---|---|
bin | 11110010001100010110… |
… | …00010010010000011011 |
3 | 10200102222001122021022211 |
4 | 33020301120102100123 |
5 | 114020322344113301 |
6 | 2113511025455551 |
7 | 135103246443553 |
oct | 17106130222033 |
9 | 3612861567284 |
10 | 1040210535451 |
11 | 37117280237a |
12 | 1497244a15b7 |
13 | 77125b53899 |
14 | 384bc97a163 |
15 | 1c0d1989051 |
hex | f23161241b |
1040210535451 has 2 divisors, whose sum is σ = 1040210535452. Its totient is φ = 1040210535450.
The previous prime is 1040210535439. The next prime is 1040210535457. The reversal of 1040210535451 is 1545350120401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1040210535451 - 213 = 1040210527259 is a prime.
It is a super-2 number, since 2×10402105354512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1040210535457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520105267725 + 520105267726.
It is an arithmetic number, because the mean of its divisors is an integer number (520105267726).
Almost surely, 21040210535451 is an apocalyptic number.
1040210535451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1040210535451 is an equidigital number, since it uses as much as digits as its factorization.
1040210535451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 1040210535451 its reverse (1545350120401), we get a palindrome (2585560655852).
The spelling of 1040210535451 in words is "one trillion, forty billion, two hundred ten million, five hundred thirty-five thousand, four hundred fifty-one".
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