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104043543211 is a prime number
BaseRepresentation
bin110000011100101111…
…0100111101010101011
3100221112222021121202101
41200321132213222223
53201040121340321
6115444050114231
710342203345136
oct1407136475253
9327488247671
10104043543211
114014095aa53
12181b7b7b977
139a7146866a
1450700ab21d
152a8e211791
hex18397a7aab

104043543211 has 2 divisors, whose sum is σ = 104043543212. Its totient is φ = 104043543210.

The previous prime is 104043543209. The next prime is 104043543269. The reversal of 104043543211 is 112345340401.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 104043543211 - 21 = 104043543209 is a prime.

Together with 104043543209, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 104043543211.

It is not a weakly prime, because it can be changed into another prime (104043543271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52021771605 + 52021771606.

It is an arithmetic number, because the mean of its divisors is an integer number (52021771606).

Almost surely, 2104043543211 is an apocalyptic number.

104043543211 is a deficient number, since it is larger than the sum of its proper divisors (1).

104043543211 is an equidigital number, since it uses as much as digits as its factorization.

104043543211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 104043543211 its reverse (112345340401), we get a palindrome (216388883612).

The spelling of 104043543211 in words is "one hundred four billion, forty-three million, five hundred forty-three thousand, two hundred eleven".