1041040141313 has 4 divisors (see below), whose sum is σ = 1041044541888. Its totient is φ = 1041035740740.

The previous prime is 1041040141261. The next prime is 1041040141357. The reversal of 1041040141313 is 3131410401401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1041040141313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1041040140313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1823981 + ... + 2325722.

It is an arithmetic number, because the mean of its divisors is an integer number (260261135472).

Almost surely, 2^{1041040141313} is an apocalyptic number.

It is an amenable number.

1041040141313 is a deficient number, since it is larger than the sum of its proper divisors (4400575).

1041040141313 is an equidigital number, since it uses as much as digits as its factorization.

1041040141313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4400574.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1041040141313 its reverse (3131410401401), we get a palindrome (4172450542714).

The spelling of 1041040141313 in words is "one trillion, forty-one billion, forty million, one hundred forty-one thousand, three hundred thirteen".